2020. 11. 26. 20:08ㆍ카테고리 없음
I Have Generated Private Key & Public Key Using Open SSL
1) openssl genrsa -out rsa.pem 1024
2) openssl rsa -in rsa.pem -pubout
I am Using pidCrypt for Encrypt in JavaScript RSA .
At Java Using Instance as RSA( Cipher.getInstance('RSA') ) .
But Output is Diffrent
JavaScript Encrypt : K2N58n/ejCzlJaZc1fQlU6+9b4ctAnc6vLIfw5TbvDbVmSLhJ7V2kE50d2+ZF9kK
199D/BFSpHorngu6xYrczUmcYB95gVGIw8xre/TuWIHvvoRu2FKQDU/bs57hVpKa
y3WEdTAe+LFq5aRGNQ2exRvSB45m18ggOAutH/5OUt0=
On Decryption I am getting Error :
javax.crypto.BadPaddingException: Message is larger than modulus
at sun.security.rsa.RSACore.parseMsg(Unknown Source)
How Does Bank Implement Secure UserName & Password.
Is Encryption In Javascript is good Idea.
Can Anyone Suggest Other Good way for Password Encrytion.
Java AES 256 Encryption Decryption Example. August 22, 2018 by Lokesh Gupta. Learn to use Java AES 256 bit encryption to create secure passwords, and decryption for password validation. To read simple AES encryption, read linked post. AES is a symmetric encryption algorithm. Encryption and Decryption in Java Cryptography. The security of encryption lies in the ability of an algorithm to generate ciphertext (encrypted text) that is not easily reverted back to its original plaintext. The use of keys adds another level of security to methods of protecting our information. Implementation of RSA Algorithm (Encryption and Decryption) in Java. Java program to encrypt and decrypt a given message using RSA algorithm. Open Command Prompt and compile & Run. RSA algorithm is used to changing message that no one can understand the communication between sender and receiver. Sender and Receiver have public and private key and they can only understand message.
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Parag Rathod wrote:5OUt0=
On Decryption I am getting Error :
javax.crypto.BadPaddingException: Message is larger than modulus
at sun.security.rsa.RSACore.parseMsg(Unknown Source)
The default Sun/Oracle RSA encryption/decryption assumes PKCS1 padding (which has a random component) and the exception suggest that your JavaScript RSA is not performing the required PKCS1 padding. This padding requirement can be turned off but failure to use the padding makes it very very easy to decrypt/crack the average password either by brute force or by 'dictionary' attack. As already suggested you should be using HTTPS then you do not need to do any explicit encryption.
[edit] It has just occurred to me that another possible cause is that you are not Base64 decoding in your Java the obviously Base64 encoded cipher text. Of course I can't see any of your code so I am just guessing.
Parag Rathod wrote:Thank You Sir...Problem got resolved i was because of Base 64 Decode.
I'm pleased to have helped BUT as has already been pointed out twice before you should probably be using HTTPS and not doing the encryption yourself.
Parag Rathod wrote:How Does Bank Implement Secure UserName & Password.
They use HTTPS.
I created a KeyStore using KeyStore Explorer with a public/private key pair inside it of type RSA, 4096 bytes, and PKCS#8 formatting.
I get an error when my code runs and hits the cipher.init() method :
'Key for algorithm RSA not suitable for symmetric encryption.'
This doesn't really make sense to me because I'm using asymmetric key encryption/decryption. I'm not sure where to go from here or what I'm doing wrong.
Rsa Algorithm Encryption And Decryption Example Java
Here is what I have:
Restful Web Services Example In Java
Any help would be great. Thanks in advance!
Dennis Kriechel1 Answer
You are trying to initialize your cipher as AES/CBC/PKCS5Padding which is an symmetric encryption and that is where the exception originates.
You should use the Cipher like that:
Here you can find a good example for RSA-Encryption and Decryption.
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